Question

Please help:Solve for t.19 = 1/2 gt^2A. t=38/g−−√B. t=76/g−−√C. t=(38/g)^2D. t=g/76−−√

Answer 1

Given:

`19=(1)/(2)gt^2`

We will solve the equation to find (t) as follows:

`\begin{gathered} 19=(1)/(2)gt^2\rightarrow*2 \\ 2*19=2*(1)/(2)gt^2 \\ 38=gt^2 \\ t^2=(38)/(g) \\ \\ t=\sqrt{(38)/(g)} \end{gathered}`

So, the answer will be the first option.