Question

What is the [OH-] in a solution of ph 3.00?

Answer 1

pH = 3, pOH = 14-3 = 11
[OH-] = 10^(-pOH) = 10^(-11) = 1E-11 or 1*10^-11

Answer 2

Answer: Thus hydroxide ion concentration is
`10^(-11)M`

Step-by-step explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration and pOH is calculated by taking negative logarithm of hydroxide ion concentration.

`pH=-\log [H^+]`

`pOH=-log{OH^-}`

`pH+pOH=14`

Given: pH=3

`3+pOH=14`

`pOH=11`

`11=-log[OH^-]`

`[OH^-]=10^(-11)`

Thus hydroxide ion concentration is
`10^(-11)M`