Question

Two large books are stacked on top of each other on a table . The mass of each book is 6.5Kg Given that the coefficient of static friction between bottom book and table is 0.15, what is the lowest the coefficient of static friction between the books can be in order to apply force and move both books?

Answer 1

The coefficient of static friction between the books and the table is 0.15. The force required to move both books can be calculated using the equation: Force of friction = coefficient of friction x Normal force. To find the lowest coefficient of static friction, you would need to rearrange the equation and solve for the coefficient of friction.

Step-by-step explanation:

The coefficient of static friction between the books and the table is given as 0.15. The force required to move both books can be calculated using the equation:

Force of friction = coefficient of friction x Normal force

Since the books are stacked on top of each other, the normal force acting on the bottom book is the weight of both books. The weight of each book is 6.5 kg multiplied by the acceleration due to gravity (9.8 m/s²). Therefore, the normal force is 6.5 kg x 9.8 m/s². Plugging in the values, we get:

Force of friction = 0.15 x (6.5 kg x 9.8 m/s²)

Solving this equation will give you the force of friction required to move both books. To find the lowest coefficient of static friction, you would need to rearrange the equation and solve for the coefficient of friction.

Answer 2

If you apply force (push) both books with the same energy at the same constant rate then the friction between them doesn't matter as both will move. If you push on the bottom book only, the friction between the books needs to be sufficient that the top book is carried along on the bottom book.