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If h(x)=3x-1 and j(x)= -2, solve h[j(2)]
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If h(x)=3x-1 and j(x)= -2, solve h[j(2)]

User MarcRo
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To do this we figure out the inner first. This is easy since it is j and j is always -2. Now we can plug -2 into h
3(-2)-1=-7
User Thisarattr
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