2 Answers

Everon · Answer 1 · 2018-01-13T19:47:25+0000

Answer:

D.
11j^2k^4

Explanation:

We are asked to find the GCF of
$44j^5k^4\text{ and }121j^2k^6$ .

Since we know that GCF of two numbers is the greatest number that is a factor of both of them.

First of all we will GCF of 44 and 121.

Factors of 44 are: 1, 2, 4, 11, 22, 44.

Factors of 121 are: 1, 11, 11, 121.

We can see that greatest common factor of 44 and 121 is 11.

Now let us find GCF of
$j^5\text{ and }j^2$ .

Factors of
j^5 are:
j*j*j*j*j

Factors of
j^2 are:
j*j

We can see that greatest common factor of
$j^5\text{ and }j^2$ is
j*j=j^2 .

Now let us find GCF of
$k^4\text{ and }k^6$ .

Factors of
k^4 are:
k*k*k*k

Factors of
k^6 are:
k*k*k*k*k*k

We can see that greatest common factor of
$k^4\text{ and }k^6$ is
k*k*k*k=k^4 .

Upon combining our all GCFs we will get,

11j^2k^4

Therefore, GCF of
$44j^5k^4\text{ and }121j^2k^6$ is
and option D is the correct choice.

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