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2 votes
3x+12-6x<-9

3x + 12 - 6x \leqslant - 9
how do I do this?

User Bonnopc
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1 Answer

6 votes
First simplify 3x + 12 - 6x to -3x - 12
Next subtract 12 from both sides
Next subtract -9 - 12 and that would be -21
Next divide both sides by -3
Next lets simplify the fraction -21/-3 into 21/3 since those two negatives make a positive.
Lastly simplify the fraction 21/3 to get the answer.


Answer: x ≥ 7

User Darwen
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8.4k points