75.1k views
2 votes
In a market research survey of 29012901 ​motorists, 255255 said that they made an obscene gesture in the previous month. complete parts​ (a) and​ (b) below.

a. if 1 of the surveyed motorists is randomly​ selected, what is the probability that this motorist did not make an obscene gesture in the previous​ month? the probability is . 9121.9121. ​(round to four decimal places as​ needed.)
b. if 5050 of the surveyed motorists are randomly selected without​ replacement, what is the probability that none of them made an obscene gesture in the previous​ month? should the​ 5% guideline be applied in this​ case? select the correct choice below and fill in the answer box within your choice. ​(round to four decimal places as​ needed.) g

User Olvagor
by
8.7k points

1 Answer

4 votes
a. 1-255255/29012901=0.991202017 is the probability of not making an obscene gesture.
b. The probability of none of 5050 making an obscene gesture is (a) raised to the power of 5050: 4.1591E-20 approx. We have not used the 5% rule in this binomial distribution.
User Agustin Meriles
by
8.3k points