Question

Assume that the partial pressure of sulfur dioxide, pso2, is equal to the partial pressure of dihydrogen sulfide, ph2s, and therefore pso2=ph2s. if the vapor pressure of water is 28 torr , calculate the equilibrium partial pressure of so2 (pso2) in the system at 298 k.

Answer 1

Kp = PH2O^2/(PH2O)^2 To calculate SO2 is to have a Kp for the reaction let x=PSO2=PH2S Kp= (28/760atm)^2/x^3 x=cube root(0.03684)/Kp=PSO2