Question

. Solve the equation gʻ + 6g + 4 = 0 by completing the square. A 15 C -3+V5 B cubed root of 5 D-3+ V5 Q

Answer 1

C

1) Let's complete the square for this quadratic equation g² +6g +4 = 0

g² +6g +4 = 0 Divide the coefficient b by 2: 6/2 = 3

Subtract 4 from both sides

g² +6g = -4 Add 9 to both sides

g² +6g +9 = -4 + 9 Rewrite it as a binomial (a+b)²

(g+3)² = 5 Take the square root on both sides

√(g+3)² = √5

g+3 =+√5, -√5 Subtract 3 from both sides

g = -3 +√5, -3 -√5

2) Hence, the roots for this quadratic equation are:

`S=\mleft\lbrace-3+\sqrt[]{5},\text{ 3-}\sqrt[]{5}\mright\rbrace`

3) Hence, the answer is C