Question

Find the product.

(n + 7)2

A. 2n² + 14n + 49
B. n² + 14n + 14
C. n² + 14n + 49

Answer 1

The little 2 next to (n+7) means squared. Therefore you have to put the same numbers twice.
(n+7)(n+7) = n2+7n+7n+49 : then add the same numbers so in this case 7n+7n which gives you :
n2+14n+49

Answer 2

if that 2 is an exponent

`(n+7)^2=(n+7)(n+7)=`

`(n+7)(n)+(n+7)(7)=`

`n^2+7n+7n+49=`

`n^2+14n+49`


or you coud use the formula

`(a+b)^2=a^2+2ab+b^2`
so

`(n+7)^2=n^2+2(n)(7)+7^2=n^2+14n+49`
answer is C