Question

What is the average acceleration of a subway train that speeds up from 9.6 m/s to 12 m/s in 0.8 s on a straight section of track? Show your work below.

Answer 1

What is the average acceleration of a subway train that speeds up from 9.6 m/s to 12 m/s in 0.8 s on a straight section of track? Show your work below.

Average acceleration = change in velocity/ change in time
=12-9.6/.8=2.4/.8=3m/s²

Answer 2

Average acceleration,
`a=3\ m/s^2`

Explanation:

Given that,

Initial speed of the train, u = 9.6 m/s

Final speed of the train, v = 12 m/s

Time taken, t = 0.8 s

Let a is the acceleration of the train. The mathematical formula for acceleration is given by :

`a=(v-u)/(t)`

`a=(12-9.6)/(0.8)`

`a=3\ m/s^2`

So, the average acceleration of the subway train is
`3\ m/s^2`. Hence, this is the required solution.