Question

A bag contains 4 sour-apple candies and 3 watermelon candies. One piece of candy is chosen at random and returned to the bag. Then a second piece of candy is chosen at random What is the probability that both pieces of candy chosen will be sour -apple ?

Answer 1

Answer:
`(16)/(49)`

Explanation:

Given: A bag contains 4 sour-apple candies and 3 watermelon candies.

Total candies = 4+3 = 7

If replacement of candy is done, then the probability of getting sour apple will be the same and independent each time .

Probability of selecting sour apple candy=
`\frac{\text{Number of sour apple candy}}{\text{Total}}`

`=\frac47`

Now , the probability that both pieces of candy chosen will be sour -apple =
`\frac47*(4)/(7)=(16)/(49)`

hence, required probability =
`(16)/(49)`