Question

What is the vertex of the parabola given by y = -(x − 2)2 − 1?

Answer 1

`\bf \qquad \textit{parabola vertex form}\\\\ \begin{array}{llll} y=a(x-{{ h}})^2+{{ k}}\\\\ x=a(y-{{ k}})^2+{{ h}} \end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\ -------------------------------\\\\ y=-(x-\stackrel{h}{2})^2\stackrel{k}{-1}\qquad \qquad \stackrel{vertex~(h,k)}{(2,-1)}`