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How many electrons does barium have to give up to achieve a noble-gas electron configuration?

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Step-by-step explanation:

Alkaline earth metals are the metals which are present in group 2 of the periodic table.

Elements of this group are beryllium, magnesium, calcium, strontium, barium and radium.

So, barium is an alkaline earth metal and its electronic configuration is
[Xe]6s^(2).

It contains two valence electrons. Therefore, in order to attain noble gas configuration it needs to lose 2 electrons.

Hence, on losing two electrons it forms
Ba^(2+) ion.

Thus, we can conclude that barium have to give up 2 electrons to achieve a noble-gas electron configuration.

User Michael Gunter
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