Question

Solve this system of linear equations. separate the x- and y- values with a coma. 6x+20y=-62

3x-9y=-12

Answer 1

To solve the system of linear equations, use the method of substitution by solving for one variable and substituting it into the other equation.

Step-by-step explanation:

To solve the system of linear equations:

6x + 20y = -62

3x - 9y = -12

We can use the method of substitution:

1. From the first equation, solve for x: x = (-62 - 20y) / 6
2. Substitute the value of x into the second equation: 3((-62 - 20y) / 6) - 9y = -12
3. Simplify and solve for y:

After finding the value of y, substitute it back into the first equation to solve for x. The solution is: x = -2, y = 4.

Answer 2

6x+20y=-62
(6x+20y) + (-20y) = -62 + (-20y)
6x+20y - 20y = -62-20y
6x = -20y - 62
6x/6 = -20y -62/6
X= - 10y+31/3 Simplified answer