Final answer:
The vertical component of the velocity for a cannonball fired at a 60-degree angle from the horizontal with an initial speed of 72.5 m/s is approximately 62.81 m/s.
Step-by-step explanation:
The question pertains to the vertical component of the velocity of a cannonball that is fired at an angle of 60.0 degrees from the horizontal with an initial speed of 72.5 m/s. To find the vertical component of the velocity, we can use the sine function, since it gives the ratio of the opposite side to the hypotenuse in a right-angled triangle. The formula to calculate the vertical component (Vv) is:
Vv = V * sin(Θ)
Where V is the initial speed, and Θ is the angle of launch. Substituting the given values into the formula:
Vv = 72.5 m/s * sin(60.0 degrees)
To solve, since sin(60 degrees) is sqrt(3)/2:
Vv = 72.5 m/s * (sqrt(3)/2) = 62.81 m/s (approx)
Therefore, the vertical component of the velocity at the time of launch is approximately 62.81 m/s.