Question

Let [n] = 1 if n is odd and 0 if n is even, for all positive integer n. if [n] * [n+8] = 0, then what is one possible value of n?

Answer 1

`[n][n+8]=0`

if either or both of
`[n]` and
`[n+8]` are 0, i.e. if one or both of
`n` and
`n+8` are even. But both will be even if
`n` is even, and odd otherwise, so any even
`n` will be a solution, e.g.
`n=2`.