1 Answer

Daynesha · Answer 1 · 2018-10-30T17:35:52+0000

Given:
$\overline{AED}$ and
$\overline{BFC}$ , AE = BF, and ED = FC.
We prove that AD = BC as follows:

Statement Reason

1.
$\overline{AED}$ and
$\overline{BFC}$ Given

2. AE + ED = AD Segment Addition Postulate
BF + FC = BC

3. AE = BF and ED = FC Given

4. BF + FC = AD Substitution

5. AD = BC Transitivity property

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