Question

Can I have help with this question I don't understand how to do it 1/2(6-y)=y find y

Answer 1

`(1)/(2)(6-y)=y`

let's find y

`(6)/(2)-(y)/(2)=y`
`\text{add }(1)/(2)y\text{ to both sides}`
`(6)/(2)-(1)/(2)y+(1)/(2)y=y+(1)/(2)y`

Therefore,

`\begin{gathered} 3=(2y+y)/(2) \\ 3=(3)/(2)y \end{gathered}`

cross multiply

`\begin{gathered} 3*2=3y \\ 6=3y \\ y=(6)/(3) \\ y=2 \end{gathered}`