To answer this question, we have the following situation:
We need to have the time in minutes as follows:
Now, we have that the unit rate for preparing 24 containers at 7.66666...minutes is:
That is 3.1304...containers per minute. If we inverse this rate, we obtain:
We can convert this time in seconds as follows:
Then, in seconds, we have that the maximum time per container is about:
Or equivalently:
19.16667 sec per container.