Question

Solve -3x^2-4x-4=0. Use the quadratic formula.

Answer 1

Let's solve your equation step-by-step.
−3x2−4x−4=0
Step 1: Use quadratic formula with a=-3, b=-4, c=-4.
x=
−b±√b2−4ac
2a
x=
−(−4)±√(−4)2−4(−3)(−4)
2(−3)
x=
4±√−32
−6

Answer:
No real solutions.

Answer 2

`x1=\frac{-2(+)2i√(2)} {3}`

`x2=\frac{-2(-)2i√(2)} {3}`

Explanation:

we have

`-3x^(2) -4x-4=0`

Rewrite (Multiply by
`-1` both sides)

`3x^(2)+4x+4=0`

The formula to solve a quadratic equation of the form
`ax^(2) +bx+c=0` is equal to

`x=\frac{-b(+/-)\sqrt{b^(2)-4ac}} {2a}`

in this problem we have

`3x^(2)+4x+4=0`

so

`a=3\\b=4\\c=4`

substitute

`x=\frac{-4(+/-)\sqrt{4^(2)-4(3)(4)}} {2(3)}`

`x=\frac{-4(+/-)√(-32)} {6}`

remember that

`i=√(-1)`

`x=\frac{-4(+/-)4i√(2)} {6}`

Simplify

`x=\frac{-2(+/-)2i√(2)} {3}`

`x1=\frac{-2(+)2i√(2)} {3}`

`x2=\frac{-2(-)2i√(2)} {3}`