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What is the equation of the line that passes through the point (5,-2)and has a slope of the fraction 6/5?

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Answer:

6x-5y-40 = 0

Explanation:

y-(-2)=6/5(x-5)

5(y+2)= 6(x-5)

5y+10 =6x-30

6x-5y-40 = 0

6x-5y-40 = 0 is the answer

User Sunadorer
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