Question

`2CH_(3)OH + 3O_(2)` →
`2CO_(2) + 4H_(2)O`how many moles of
`CH_(3)OH` are needed to produce 3 moles of
`CO_(2)`?

Answer 1

1) Balance the chemical equation.

`CH_3OH+O_2\rightarrow CO_2+H_2O`

2) List the elements in the reactant and in the products.

Reactants:

C: 1

H: 4

O: 3

Products:

C: 1

H: 2

O: 3

BalanceH.

Reactants:

C: 1

H: 4

O: 3

Products:

C: 1

H: 4

O: 4

Balance oxygen

Multiply every coefficient by the denominator

Reactants:

C: 2

H: 8

O: 8

Products:

C: 2

H: 8

O: 8

3) Moles of CH3OH needed to produce 3 mol CO2.

The molar ratio between CH3OH and CO2 is 2 mol CH3OH: 2 mol CO2.

`mol\text{ }CH_3OH=3\text{ }mol\text{ }CO_2*\frac{2\text{ }mol\text{ }CH_3OH}{2\text{ }mol\text{ }CO_2}`
`mol\text{ }CH_3OH=3\text{ }mol\text{ }CH_3OH`

The moles of CH3OH needed are 3 mol.

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