13.2k views
5 votes
Lou and Jacob each sold 200 pieces of jewelry. If 20% of Lou’s sales were rings, and Jacob sold 35 rings, who sold more rings? How many more? Use the drop-down menus to explain your answer

2 Answers

5 votes
Lou sold more rings because if you multiply 200 by .20 it will be 40 which means he sold 40 rings. he sold 5 more rings than Jacob.
User Iurii Drozdov
by
7.3k points
4 votes

Answer: Lou sold more rings ( 40). He sold 5 more rings than Jacob

Explanation:

Hi, to solve this problem we have to analyze the information given:

  • Lou: 200 pieces sold- 20% were rings
  • Jacob: 200 pieces sold - 35 were rings

We have to multiply the pieces sold by Lou (200) by the percentage given in the decimal form (20% /100=0.2), to obtain the numbers of rings sold by Lou.

Mathematically speaking:

200 x 0.2 = 40 rings

40 (Lou)> 35 (Jacob)

Lou sold more rings (40 > 35). He sold 5 more rings than Jacob (40-35 =5)

User Ajeetkumar
by
5.5k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.