Question

What value of k makes the equation true? (5a^2b^3)(6a^kb)=30a^6b^4

Answer 1

the answer to your question is 4

Answer 2

k = 4

Explanation:

Given:
`(5a^2b^3)(6a^kb)=30a^6b^4`

Exponent law:

`x^m\cdot x^n=x^(m+n)`

`x^m/ x^n=x^(m-n)`

`5\cdot 6\cdot a^2\cdot a^k\cdot b^3\cdot b=30a^6b^4`

`30a^(2+k)b^(3+1)=30a^6b^4`

Compare the coefficient and power both sides

`30=30`

`a^(2+k)=a^6`

`b^4=b^4`

Exponent must be equal if base is equal.

Thus, 2+k = 6

k = 6 - 2

k = 4

Hence, The vaue of k is 4