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HELP NOW PLEASEEEEEEEEEEEE ANSWER NEEDS TO B POSITIVE

HELP NOW PLEASEEEEEEEEEEEE ANSWER NEEDS TO B POSITIVE-example-1
User Pablorc
by
3.1k points

2 Answers

8 votes

Answer:

1

Explanation:

So first we do (x^5)^2 which we know is just x^10 because of exponents of powers I believe it's called, basically you just multiply the two powers.

Then you do the bottom half which is x^3 * x^7 and that equals x^10 because of the product of exponent rule,

Then we do x^10/x^10 which = 1 because the same number over the same number is always 1.

Let me know if you have any questions

User Tarun Dholakiya
by
4.0k points
1 vote

Answer:

Solving the expression:
((x^5)^2)/((x^7)(x^3)) the answer is 1

Explanation:

We need to solve the expression:
((x^5)^2)/((x^7)(x^3))

We know that exponent rule:
(a^m)^n=a^(m*n)

Applying this rule in numerator


((x^5)^2)/((x^7)(x^3))\\=((x^(5*2)))/((x^7)(x^3))\\=((x^(10)))/((x^7)(x^3))

We know the exponent rule:
(a^m).(a^n)=a^(m+n)


=((x^(10)))/(x^(7+3))\\=((x^(10)))/(x^(10))

Now, using the exponent rule:
(a^m)/(a^n)=a^(m-n)


=x^(10-10)\\=x^0

We know that
a^0=1

So,
x^0=1

Solving the expression:
((x^5)^2)/((x^7)(x^3)) the answer is 1

User James In Indy
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3.5k points