Question

5t*2 -64/3t+17
HOW...? FACTOR??

Answer 1

Not factorable.

Explanation:

Since the middle term is 64/3 which cannot be simplified into a whole number, the quadratic can not be factored. To factor when a is not 1, multiply 5 and 17 to get 85. Then find two numbers which multiply to 85 and add to -64/3 or -21.333.... It cannot be done. Instead solve using the quadratic formula.

The quadratic formula is
`x=(-b+/-√(b^2-4ac) )/(2a)`. Here a=5, b=-64/3, and c=17.

Substitute and you'll have:

`x=(-b+/-√(b^2-4ac) )/(2a) =\frac{(64)/(3)+/-\sqrt{{(64)/(3)}^2-4(5)(17)} }{2(5)}=(21.333..+/-√(455.1111...-340) )/(10))`

`(21.333..+/-√(115.1111...) )/(10)) = (21.333..+/- 10.73)/(10)) = 3.2, 1.06`

These are approximations since 64/3 and other numbers were rounded in the calculation.