Question

You don't have to show me how to do it you can just put the answer

Answer 1

The form of the linear equation is

`y=mx+b`

m is the slope of the line

b is the y-intercept

Since the slope of the line is -4, then

m = -4

`y=-4x+b`

To find b substitute x and y in the equation by the coordinates of a point on the line

Since point (1, 2) lies on the line, then

x = 1

y = 2

`\begin{gathered} 2=-4(1)+b \\ 2=-4+b \end{gathered}`

Add 4 to both sides

`\begin{gathered} 2+4=-4+4+b \\ 6=b \end{gathered}`

Then the equation of the line is

`y=-4x+6`

To put it in the slope point form use this form

`y-y_1=m(x-x_1)`

m = -4

x1 = 1

y1 = 2

`y-2=-4(x-1)`

The answer is

`y-2=-4(x-1)`