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The sum of two consecutive even integers is 22 less than four times the smallest of the two numbers. Find the larger of the two integers

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Let the two consecutive even numbers be 'A' and 'B' (A being the lesser and B the larger)

Based on the question, A + B = 4A - 22 (1)
since B is a consecutive even number to A, then B = A + 2 (2)

By substituting (2) into (1),
A + (A + 2) = 4A - 22
2A + 2 = 4A - 22
2 + 22 = 2A
A = 12

Now, if A = 12,
then B = 14

∴ the two integers are 12 and 14.



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