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HELP!!! you dont have to answer all the questions at least the first one!!! 57x^5 / 19x^2 What is the excluded value(s) of the variable? How did you you find the value? and why it works?
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HELP!!! you dont have to answer all the questions at least the first one!!!

57x^5 / 19x^2
What is the excluded value(s) of the variable?
How did you you find the value?
and
why it works?

User Rimkashox
by
8.2k points

1 Answer

5 votes
57/19 = 3
x^5 / x^2 = x^(5-2) = x^3

so 57x^5 / 19x^2 = 3x^3

answer
3x^3
User Jalani
by
7.9k points
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