Question

What is the equation of the line that passes through the point (4,0) and has a slope
of -3/4?

Answer 1

`y = -(3)/(4)x + 3`

Explanation:

The slope-intercept form of a line equation is

y = mx + b

where m = slope

b = y-intercept

We are given slope:

`-(3)/(4)`

So equation must be of the form

`y = -(3)/(4)x + b`

Since line passes through (4,0), this point coordinates must satisfy the equation

Substitute for y = 0 when x = 4 to get

`0 = -(3)/(4)\cdot 4 + b\\\\\\0 = -3 + b\\\\b = 3\\\\\text{Equation of the line is }y = -(3)/(4)x + 3`