Question

102.26 GRAMS OF ZINC TO ATOMS

Answer 1

The number of atoms of zinc in 102.26 grams is 9.42 x 10^23 atoms

Step-by-step explanation

Given that;

The mass of zinc is 102.26 grams

Follow the steps below to find the number of atoms

Step 1; Find the mole of the zinc atom using the formula below

`\text{ mole = }\frac{\text{ mass}}{\text{ molar mass}}`

Recall, that the unit mass of zinc is 65.38u

`\begin{gathered} \text{ mole = }\frac{\text{ 102.26}}{\text{ 65.38}} \\ \text{ mole = 1.564 moles} \end{gathered}`

Step 2; Find the number of atoms of zinc using the below formula

`\text{ mole = }\frac{\text{ Number of atoms}}{\text{ Avogadro's number}}`

Recall, that the Avogadro's constant is 6.022 x 10^23

`\begin{gathered} \text{ 1.564 = }\frac{\text{ number of atoms}}{\text{ 6.022}*10^(22)} \\ \text{ cross multiply} \\ \text{ Number of atoms = 1.564 }*\text{ 6.022 }*\text{ 10}^(23) \\ \text{ Number of atoms = 9.42 }*\text{ 10}^(23)\text{ atoms} \end{gathered}`

Therefore, the number of atoms of zinc in 102.26 grams is 9.42 x 10^23 atoms