Question

I don’t understand how to solve this graph.
(Y=MX+B)

Answer 1

The equation of line shown in the graph is
`\mathbf{y=-(1)/(2)x -1}`

Explanation:

We need to find equation of the line shown in graph.

The equation of line will be in slope-intercept form
`y=mx+b` where m is slope and b is y-intercept.

We need to find slope and y-intercept.

Finding y-intercept

Looking at the graph, we can find y-intercept when x =0, the value of y is known as y-intercept.

So, when x =0, y=-1

So, y-intercept is -1

Finding Slope

Now, for finding slope, consider 2 points on graph

(0,-1) and (-2,0)

Slope can be found using formula:
`Slope=(y_2-y_1)/(x_2-x_1)`

We have
`x_1=0, y_1=-1, x_2=-2, y_2=0`

Putting values and finding slope:

`Slope=(y_2-y_1)/(x_2-x_1)\\Slope=(0-(-1))/(-2-0) \\Slope=(0+1)/(-2-0) \\Slope=(1)/(-2) \\Slope=-(1)/(2)`

So, slope is
`m=-(1)/(2)`

Equation of line

Now, equation of line having slope
`m=-(1)/(2)` and y-intercept b = -1 is

`y=mx+b\\y=-(1)/(2)x -1`

So, equation of line shown in the graph is
`\mathbf{y=-(1)/(2)x -1}`