Question

6) How many milliliters of water must be added to 139 mL of 1.50 M HCl to give 1.00 M HCl? (Assume the volumes are additive.)

Answer 1

Given:

V1 = 139 mL

C1 = 1.50 M

C2 = 1.00 M

V2 = ?

The following equation can be used to solve the problem:

C1V1 = C2V2

V2 = (C1V1)/C2

V2 = (1.50 M x 139 mL)/1.00M

V2 = 208.5 mL