Question

There are 4 consecutive integers that have a sum of 58. what is the least of these integers?

Answer 1

Easy way
58÷4= 14.5 is center of the integers

13 is the least of these integers
14
15
16

Equations:
4 consecutive numbers
X, X+1, X+2, X+3
13, 14, .. 15 ...16

X + X+1 + X+2 + X+3 = 58
4X + 6 = 58
4X = 58-6 = 52
X = 52/4 = 13