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If a 10.0 g mass of aluminum increases from 20.0 °C to 35.0 °C, how much heat was required? (0.903 J/g°C)

If a 10.0 g mass of aluminum increases from 20.0 °C to 35.0 °C, how much heat was required? (0.903 J/g°C)
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If a 10.0 g mass of aluminum increases from 20.0 °C to 35.0 °C, how much heat was required? (0.903 J/g°C)

User Tillito
by
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1 Answer

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the amount of heat is calculated with the formula

q= m x Ce x ΔT

q= heat
m= mass
Ce= specific heat
ΔT= change in temperature
m= 10.0 g
Ce = 0.903 J/gC
ΔT = Tf - Ti = 35.0 - 20.0= 15

q= 10.0g x 0.903 J/gC x 15 = 135.45 J

User Svidgen
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