Final answer:
The mass of 1.63x10^21 silicon atoms is calculated to be approximately 0.07596 grams by converting the number of atoms into moles and then multiplying by the atomic mass of silicon.
Step-by-step explanation:
The mass of 1.63x10^21 silicon atoms can be calculated using the concept of moles and the atomic mass unit (amu). One mole of silicon contains Avogadro's number (6.022x10^23) of atoms and has a mass of approximately 28.0855 grams, as the atomic mass of silicon is 28.0855 amu. To find the mass of 1.63x10^21 silicon atoms, we first convert the number of atoms to moles by dividing by Avogadro's number, and then we multiply by the molar mass of silicon:
Number of moles = 1.63x10^21 atoms / 6.022x10^23 atoms/mole = 2.705x10^-3 moles.
Mass in grams = 2.705x10^-3 moles x 28.0855 g/mole = 0.07596 g.
Therefore, the mass of 1.63x10^21 silicon atoms is approximately 0.07596 grams.