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What are the zeros of (x^3-5x^2+2x+8)/(x+1)
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What are the zeros of (x^3-5x^2+2x+8)/(x+1)

User Thegunner
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1 Answer

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the roots are 2 and 4
Here is how I did it:
it is hard to factor the numerator, so I used long division, divide the numerator by the denominator, the quotient is x^2-6x+8, which can be factor into (x-2)(x-4)
User Fabian Lauer
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