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Write equation of a line that is parallel to 2y+8x=4 and passing through the point (2,-3)

User Stackex
by
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1 Answer

11 votes
Answer: y=-4x+5


Step-by-step explanation:

First, put the given equation into point-slope form.

2y+8x=4
2y=-8x+4
y=-4x+2

Now to get the slope of a line parallel to this, we keep the same constant before x (-4)

y=-4x

Since this follows the point-slope form y=mx+b, we just need to find the value of b so that the line passes through (2,-3).
Since we are given those x and y values, we can plug those numbers into y=mx+b


y=-4x+b
-3=-4(2)+b
-3=-8+b
5=b

This is the value of b, which we can plug back into our equation

y=-4x+b

y=-4x+5

User Vkjgr
by
6.2k points
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