Question

Prealgebra- Find an equation of the line that passes through the given point and has the indicated slope m.

Answer 1

Given:

Slope, m = 1/3

Point: (x, y) ==> (-7, -3)

Let's find the equation of the line that passes through the point with the indicated slope.

Apply the slope-intercept form:

`y=mx+b`

Where:

m is the slope.

b is the y-intercept.

Plug in 1/3 for m, then input the coordinates of the point (-7, -3) for the values of x and y respectively, then solve for b.

We have:

`\begin{gathered} -3=(1)/(3)(-7)+b \\ \\ -3=-(7)/(3)+b \\ \\ b=-3+(7)/(3) \\ \\ b=(3(-3)+1(7))/(3) \\ \\ b=(-9+7)/(2) \\ \\ b=-(2)/(3) \end{gathered}`

Therefore, the y-intercept of the line is:

b = -2/3

Hence, the equation of the line in slope-intercept form is:

`y=(1)/(3)x-(2)/(3)`

• ANSWER:

`y=(1)/(3)x-(2)/(3)`