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If the circle (x - 5)2 + (y - 3)2 = 6 is translated 4 units to the left and 1 unit up, what is the center of the circle?

If the circle (x - 5)2 + (y - 3)2 = 6 is translated 4 units to the left and 1 unit up, what is the center of the circle?
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If the circle (x - 5)2 + (y - 3)2 = 6 is translated 4 units to the left and 1 unit up, what is the center of the circle?

User Dharmesh Goswami
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8.9k points

1 Answer

5 votes
the original center is at (5,3)
4 units to the left means 5+(-4)=1
1 unit up means 3+1=4
so the new center is at (1,4)
the equation become (x-1)^2 + (y-4)^2 =6
User Lalit Goswami
by
8.2k points
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