126k views
0 votes
Find the equation of a line parallel to y - 5x = 10 that passes through the point (3, 10). (answer in slope-intercept form)

A) y = 5x - 5
B) y = 5x + 5
C) y = -5x - 5
D) y =
1
5
x - 5

2 Answers

6 votes

Answer:

A

Explanation:

User Nino Amisulashvili
by
8.0k points
7 votes
so, a line parallel to y - 5x = 10, will have the same slope as that equation, so what is that slope anyway? let's solve for "y".


\bf y-5x=10\implies y=5x+10\implies y=\stackrel{slope}{5}x\stackrel{y-intercept}{+10}

alrite, so the slope is 5 then, well, then the parallel line will have the same slope.

so, we're really looking for the equation of a line whose slope is 5 and runs through 3,10.



\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ 3}}\quad ,&{{ 10}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies 5 \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-10=5(x-3) \\\\\\ y-10=5x-15\implies y=5x-5
User Nullglob
by
9.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories