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Find the equation of a line parallel to y - 5x = 10 that passes through the point (3, 10). (answer in slope-intercept form)

A) y = 5x - 5
B) y = 5x + 5
C) y = -5x - 5
D) y =
1
5
x - 5

2 Answers

6 votes

Answer:

A

Explanation:

User Nino Amisulashvili
by
8.0k points
7 votes
so, a line parallel to y - 5x = 10, will have the same slope as that equation, so what is that slope anyway? let's solve for "y".


\bf y-5x=10\implies y=5x+10\implies y=\stackrel{slope}{5}x\stackrel{y-intercept}{+10}

alrite, so the slope is 5 then, well, then the parallel line will have the same slope.

so, we're really looking for the equation of a line whose slope is 5 and runs through 3,10.



\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ 3}}\quad ,&{{ 10}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies 5 \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-10=5(x-3) \\\\\\ y-10=5x-15\implies y=5x-5
User Nullglob
by
9.5k points

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