In order to find the zeros of the function, we can factor the polynomial by grouping.
x³ - 3x² + 16x - 48
= x²(x - 3) + 16(x - 3)
= (x² + 16)(x - 3)
Solve for the zeros:
1) x - 3 = 0
Solution: x = 3
The non repeated x-intercept is 3. The polynomial has the zero of 3 multiplicity 1.
2) x² + 16 = 0
x² = -16
x = ±√-16
x = ± i√16
x = ± 4i
Solution: x = 0 + 4i and and x = 0 - 4i
The complex zeros of the function in a + bi form is 0 ± 4i. The function has a total of two complex zeros.