Question

PLEASE HELP ASAP

a boy swings a bucket containing 2.4 kg of water in a vertical circle of radius 0.6 m at a constant rotational rate of 1 revolution every 1.4 seconds. Find the following quantities:


the angular speed of water in rad/sec


the tangential speed of the water in meters/sec

Answer 1

a) ω = 4.49 rad/s

b) v = 2.69 m/s

Step-by-step explanation:

a) The angular speed can be found by using the rotational rate:

`\omega = (1 rev)/(1.4 s)*(2\pi rad)/(1 rev) = 4.49 rad/s`

Hence, the angular speed is 4.49 rad/s.

b) The tangential speed is given by:

`v = \omega*r = 4.49 rad/s*0.6 m = 2.69 m/s`

Therefore, the tangential speed is 2.69 m/s.

I hope it helps you!