Question

How many liters of oxygen gas (O2) are needed to produce 100 kJ of energy at STP? 2C6H6(I) + 1502(g) —> 12CO2(g)+6H2O(g)+3909.9 kJ

Answer 1

Answer: 8.59 L of oxygen gas are needed to produce 100 kJ of energy at STP

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
`6.023* 10^(23)` of particles.

Standard condition of temperature (STP) is 273 K and atmospheric pressure is 1 atmosphere respectively.

1 mole of every gas occupy volume at STP = 22.4 L

The balanced chemical reaction is:

`2C_6H_6(I)+15O_2(g)\rightarrow 12CO_2(g)+6H_2O(g)`

3909.9 kJ of of energy is produced by =
`15* 22.4=336L`

100 kJ of oxygen gas are needed to produce =
`(336)/(3909.9)* 100=8.59L`