Question

One number is 9 times a first number. a third number is 100 more than the first number. if the sum of the three numbers is 606​, find the numbers.

Answer 1

let first number = x then

we have x and 9x and x + 100

x + 9x + x + 100 = 606
11x + 100 = 606
11x = 506
x = 46

so the three numbers are 46, 146 and 414 Answer