Question

The equation shows the reaction between zinc metal and hydrochloric acid.

Zn(s) + 2HCl(aq) mc014-1.jpg ZnCl2(aq) + H2(g)


What is the theoretical yield of hydrogen gas if 5.00 mol of zinc are added to an excess of hydrochloric acid?
a.5.05 g
b.10.1 g
c.182 g
d.682 g

Answer 1

10.1g

Step-by-step explanation:

Answer 2

Answer: 10 grams of Hydrogen gas will be produced theoretically.

Explanation: The equation for the reaction between zinc metal and hydrochloric acid is:

`Zn(s)+2HCl(aq.)\rightarrow ZnCl_2(aq.)+H_2(g)`

As HCl is present in excess, therefore limiting reagent is Zinc metal as it limits the formation of product.

By stoichiometry,

1 mole of Zinc metal produces 1 mole of Hydrogen gas, therefore

`\text{5 moles of Zinc metal will produce}=(1)/(1)* 5=5\text{ moles of Hydrogen gas}`

Amount of Hydrogen gas produced can be calculated by:

`\text{Mass of gas produced}=\text{Moles}* \text{Molar mass}`

Molar mass of Hydrogen = 2 g/mol

Mass of hydrogen gas produced = (5 moles )× (2 g/mol)

Mass of hydrogen gas produced = 10 grams