Question

If 65.5 ml of HCl stock solution is used to make 450 ml of a 0.675 M HCl dilution, what is the molarity of the stock solution ?

Answer 1

4.64M

Step-by-step explanation:

Dilution Problems Worksheet

1. How do you prepare a 250.-ml of a 2.35 M HF dilution from a 15.0 M stock solution?

39.2 mL

2. If 455-ml of 6.0 M HNO3 is used to make a 2.5 L dilution, what is the molarity of the dilution?

1.1 M

3. If 65.5 ml of HCl stock solution is used to make 450.-ml of a 0.675 M HCl dilution, what is the molarity of the stock solution?

4.64 M

4. How do you prepare 500.-ml of a 1.77 M H2SO4 dilution from an 18.0 M H2SO4 stock solution?

Take 49.2-ml of 18.0 M H2SO4 stock solution and pour it into a 500-ml volumetric flask. Fill to the 500-ml line with distilled water to make 1.77M H2SO4 solution.

Extra Molarity Problems for Practice

1. How many moles of LiF would be required to produce a 2.5 M solution with a volume of 1.5 L?

3.75 M

2. How many moles of Sr(NO3)2 would be used in the preparation of 2.50 L of a 3.5 M solution?

8.75 M

3. What is the molarity of a 500-ml solution containing 249 g of KI?

3.00 M

4. How many grams of CaCl2 would be required to produce a 3.5 M solution with a volume of 2.0 L?

777 g

Answer 2

Answer: The molarity of the stock solution is 4.64 M

Step-by-step explanation:

To calculate the molarity of the diluted solution, we use the equation:

`M_1V_1=M_2V_2`

where,

`M_1\text{ and }V_1` are the molarity and volume of the stock solution

`M_2\text{ and }V_2` are the molarity and volume of diluted solution

We are given:

`M_1=?M\\V_1=65.5mL\\M_2=0.675M\\V_2=450mL`

Putting values in above equation, we get:

`M_1* 65.5=0.675* 450\\\\M_1=4.64M`

Hence, the molarity of the stock solution is 4.64 M