Answer:
hello your question is incomplete attached below is the complete question
answer :
Fe2O3 = 159 g/mol
CO = 28.01 g/mol
Fe = 55.85 g/mol
CO2 = 44.01 g/mol
Step-by-step explanation:
Fe = 55.85 g/mol
O = 16.0 g/mol
hence the molar mass of Fe2O3 = 2(55.85) + 3(16) = 159 g/mol
C = 12.01 g/mol
O = 16.0 g/mol
hence the molar mass of CO = 28.01 g/mol
Fe = 55.85 g/mol
C = 12.01 g/mol
O = 16.0 g/mol
hence the molar mass of CO2 = 12.01 + 2(16) = 44.01 g/mol