As the mean is E[X] =150 and

= 30, using the normal distribution to get the answer is just using Z. So, what we need is P(X<180).
![Z= (x-E[X])/(\sigma ) = (180-150)/(30) = (30)/(30) = 1](https://img.qammunity.org/2018/formulas/mathematics/high-school/jtdd3ielcntjm2vu96w8nwp4xli15imxqa.png)
P(x<180) = P(z< 1) =

(1) = 0.8413.
Then, just multiplying the amount of books you have, which is 500, with the probability would give how many books are less than 180 pages, being:
